计算机阅读该程序，给出程序的输出结果。 #include <iostream.h> class B { public:     virtual void fun1()     {         cout<<"B::fun1().n";     }     virtual void fun2()     {         cout<<"B::fun2().n";     }     void fun3()     {         cout<<"B::fun3().n";     }     void fun4()     {         cout<<"B::fun4().n";     } }; class D:public B { public:     void fun1()     {         cout<<"D::fun1().n";     }     void fun2()     {         cout<<"D::fun2().n";     }     void fun3()     {         cout<<"D::fun3().n";     }     void fun4()     {         cout<<"D::fun4().n";     } }; void main() {     B *pb;     D d;     pb=&d;     pb->fun1();     pb->fun2();     pb->fun3();     pb->fun4(); }-笔试面试资料

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答案：

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提供答案分析，通过本文《阅读该程序，给出程序的输出结果。 #include <iostream.h> class B { public:     virtual void fun1()     {         cout<<"B::fun1().n";     }     virtual void fun2()     {         cout<<"B::fun2().n";     }     void fun3()     {         cout<<"B::fun3().n";     }     void fun4()     {         cout<<"B::fun4().n";     } }; class D:public B { public:     void fun1()     {         cout<<"D::fun1().n";     }     void fun2()     {         cout<<"D::fun2().n";     }     void fun3()     {         cout<<"D::fun3().n";     }     void fun4()     {         cout<<"D::fun4().n";     } }; void main() {     B *pb;     D d;     pb=&d;     pb->fun1();     pb->fun2();     pb->fun3();     pb->fun4(); }-笔试面试资料》可以理解其中的代码原理,这是一篇很好的求职学习资料
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答案：

阅读该程序，给出程序的输出结果。

#include <iostream.h>

class B

{

public:

    virtual void fun1()

    {

        cout<<"B::fun1().n";

    }

    virtual void fun2()

    {

        cout<<"B::fun2().n";

    }

    void fun3()

    {

        cout<<"B::fun3().n";

    }

    void fun4()

    {

        cout<<"B::fun4().n";

    }

};

class D:public B

{

public:

    void fun1()

    {

        cout<<"D::fun1().n";

    }

    void fun2()

    {

        cout<<"D::fun2().n";

    }

    void fun3()

    {

        cout<<"D::fun3().n";

    }

    void fun4()

    {

        cout<<"D::fun4().n";

    }

};

void main()

{

    B *pb;

    D d;

    pb=&d;

    pb->fun1();

    pb->fun2();

    pb->fun3();

    pb->fun4();

}

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